2.2.2

Specific heat capacity

Cambridge IGCSE Physics (0625)  · Unit 2: Thermal physics  · 8 flashcards

Specific heat capacity is topic 2.2.2 in the Cambridge IGCSE Physics (0625) syllabus , positioned in Unit 2 — Thermal physics , alongside States of matter, Particle model and Gases and the absolute scale of temperature.  In one line: Specific heat capacity is the energy required per unit mass per unit temperature increase. It is the amount of energy needed to raise the temperature of 1 kg of a substance by 1 °C (or 1 K).

This topic is examined in Paper 1 (multiple-choice) and Papers 3/4 (theory), plus Paper 5 or Paper 6 (practical / alternative to practical).

The deck below contains 8 flashcards — 1 definition — covering the precise wording mark schemes reward.  Use the definition card to lock down command-word answers (define, state), then move on to the concept and application cards to handle explain, describe and compare questions.

Key definition

Specific heat capacity

Specific heat capacity is the energy required per unit mass per unit temperature increase. It is the amount of energy needed to raise the temperature of 1 kg of a substance by 1 °C (or 1 K).

What the Cambridge 0625 syllabus says

Official 2026-2028 spec

These are the exact learning objectives Cambridge sets for this topic. Match the command word (Describe, Explain, State, etc.) in your answer to score full marks.

  1. Know Know that a rise in the temperature of an object increases its internal energy
  2. Describe Describe an increase in temperature of an object in terms of an increase in the average kinetic energies of all of the particles in the object Supplement
  3. Define Define specific heat capacity as the energy required per unit mass per unit temperature increase; recall and use the equation C = ΔΕ/mA0 Supplement
  4. Describe Describe experiments to measure the specific heat capacity of a solid and a liquid Supplement
Key Concept Flip

A 50g block of aluminium absorbs 450J of energy. Calculate the rise in temperature of the aluminium block. (Specific heat capacity of aluminium = 900 J/kg°C)

Answer Flip

ΔT = Q / (m * c)
ΔT = 450 J / (0.05 kg * 900 J/kg°C)
ΔT = 10°C

The rise in temperature is calculated by dividing the energy absorbed by the product of the mass and specific heat capacity. This relationship stems from the definition of specific heat capacity.

Key Concept Flip

Explain, using the concept of internal energy, why heating a metal block causes its temperature to increase.

Answer Flip

Heating a metal block increases the kinetic energy of its constituent particles (atoms or molecules). This increased kinetic energy corresponds to an increase in the block's internal energy. Temperature is a measure of the average kinetic energy of these particles. Therefore, an increase in internal energy, due to the increased kinetic energy of the particles, results in a rise in the block's temperature.

Key Concept Flip

Explain how an increase in temperature of a copper block relates to the kinetic energy of its particles.

Answer Flip

As the temperature of the copper block increases, the average kinetic energy of the copper atoms increases. This means the copper atoms vibrate more vigorously around their fixed positions in the lattice structure. The higher the temperature, the greater the average kinetic energy and the faster the vibrations.

Key Concept Flip

Describe how the average kinetic energy of particles within a substance changes as its temperature increases. Use the terms 'motion' and 'temperature' in your answer.

Answer Flip

As temperature increases, the average kinetic energy of the particles increases. This means the particles move faster (translational, rotational, or vibrational motion, depending on the state of matter). Temperature is a measure of the average kinetic energy of the particles.

Definition Flip

Define specific heat capacity.

Answer Flip

Specific heat capacity is the energy required per unit mass per unit temperature increase. It is the amount of energy needed to raise the temperature of 1 kg of a substance by 1 °C (or 1 K).

Key Concept Flip

A 0.5 kg block of aluminum absorbs 10,000 J of heat energy. If the initial temperature of the block was 20°C, and the specific heat capacity of aluminum is 900 J/(kg°C), calculate the final temperature of the block.

Answer Flip

Formula: ΔE = mcΔθ
Rearrange for Δθ: Δθ = ΔE / (mc)
Δθ = 10000 J / (0.5 kg * 900 J/(kg°C))
Δθ = 22.22 °C
Final temperature = Initial temperature + Δθ
Final temperature = 20°C + 22.22°C = 42.22°C
Answer: 42.22 °C

Key Concept Flip

Describe an experiment to determine the specific heat capacity of a solid metal block using an electrical method. Include the measurements you would take and how you would use them to calculate the specific heat capacity.

Answer Flip

Experimental Setup:
1. Insulate the metal block to reduce heat loss.
2. Insert a heater and a thermometer into the block.
3. Record the initial temperature (θ₁).
4. Turn on the heater and record the voltage (V) and current (I).
5. After a measured time (t), record the final temperature (θ₂).

Measurements:
* Mass of the block (m) in kg
* Initial temperature (θ₁) in °C
* Final temperature (θ₂) in °C
* Voltage (V) in V
* Current (I) in A
* Time (t) in s

Calculation:
1. Electrical energy supplied = V × I × t
2. Heat gained by the block = mc(θ₂ - θ₁)
3. Equate the two: V × I × t = mc(θ₂ - θ₁)
4. Rearrange to find c: c = (V × I × t) / (m × (θ₂ - θ₁))

*Explanation: This method uses electrical energy, which can be accurately measured, to heat a known mass of the solid. By measuring the temperature rise and knowing the energy input, the specific heat capacity can be determined.*

Key Concept Flip

A student uses an immersion heater to heat 0.25 kg of water in a beaker. After 5 minutes (300 s) of heating with a 50 W heater, the temperature of the water increases from 20 °C to 35 °C. Calculate the specific heat capacity of water based on this experiment.

Answer Flip

Formula:
* Energy supplied (E) = Power (P) × Time (t)
* Energy absorbed (E) = mass (m) × specific heat capacity (c) × temperature change (Δθ)
* c = E / (m × Δθ)

Working:
1. Calculate the energy supplied by the heater: E = P × t = 50 W × 300 s = 15000 J
2. Calculate the temperature change: Δθ = 35 °C - 20 °C = 15 °C
3. Calculate the specific heat capacity: c = 15000 J / (0.25 kg × 15 °C) = 4000 J kg⁻¹ °C⁻¹

Answer:
The specific heat capacity of water calculated from this experiment is 4000 J kg⁻¹ °C⁻¹.

*Explanation: This calculation uses the energy supplied to the water to determine the amount of heat required to raise the temperature of 1kg of water by 1°C.*

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2.2.1 Thermal expansion of solids, liquids and gases 2.2.3 Melting, boiling and evaporation

Key Questions: Specific heat capacity

Define specific heat capacity.

Specific heat capacity is the energy required per unit mass per unit temperature increase. It is the amount of energy needed to raise the temperature of 1 kg of a substance by 1 °C (or 1 K).

More topics in Unit 2 — Thermal physics

Specific heat capacity sits alongside these Physics decks in the same syllabus unit. Each uses the same spaced-repetition system, so progress in one informs the next.

Key terms covered in this Specific heat capacity deck

Every term below is defined in the flashcards above. Use the list as a quick recall test before your exam — if you can't define one of these in your own words, flip back to that card.

Specific heat capacity

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