3.2

Gradient and length

Cambridge IGCSE Mathematics (0580)  · Unit 3: Coordinate geometry  · 9 flashcards

Gradient and length is topic 3.2 in the Cambridge IGCSE Mathematics (0580) syllabus , positioned in Unit 3 — Coordinate geometry , alongside Coordinates and Equations of lines.

This topic is examined across Paper 1 (Core) or Paper 2 (Extended) — non-calculator — and Paper 3 (Core) or Paper 4 (Extended) — calculator.

The deck below contains 9 flashcards — 5 key concepts — covering the precise wording mark schemes reward.

Questions this Gradient and length deck will help you answer

Key Concept Flip

What is the formula to calculate the gradient (m) of a line given two points (x₁, y₁) and (x₂, y₂)?

Answer Flip

The gradient, often denoted as 'm', is calculated as the change in y divided by the change in x. The formula is: m = (y₂ - y₁) / (x₂ - x₁).

Example: points (1, 2) and (3, 6) have a gradient of (6-2)/(3-1) = 2.
Key Concept Flip

Explain the meaning of 'rise over run' in the context of gradient.

Answer Flip

'Rise over run' is a visual representation of gradient. 'Rise' refers to the vertical change (change in y), and 'run' refers to the horizontal change (change in x). The gradient is the ratio of the rise to the run.

Key Concept Flip

Calculate the length of the line segment connecting points A(2, 3) and B(5, 7).

Answer Flip

Use the distance formula (Pythagoras): √[(x₂ - x₁)² + (y₂ - y₁)²]. So, length AB = √[(5-2)² + (7-3)²] = √(9 + 16) = √25 = 5.

Key Concept Flip

Describe how the Pythagorean theorem relates to finding the distance between two points on a coordinate plane.

Answer Flip

The distance between two points is the hypotenuse of a right-angled triangle. The legs of the triangle are the difference in x-coordinates and the difference in y-coordinates. Thus, a² + b² = c² (distance squared).

Key Concept Flip

Find the midpoint of the line segment joining the points (1, 4) and (5, 2).

Answer Flip

The midpoint is found by averaging the x-coordinates and averaging the y-coordinates. Midpoint = [(x₁ + x₂) / 2, (y₁ + y₂) / 2]. Therefore, the midpoint is [(1+5)/2, (4+2)/2] = (3, 3).

Key Concept Flip

Explain what a negative gradient indicates about the slope of a line.

Answer Flip

A negative gradient indicates that the line slopes downwards from left to right. As the x-value increases, the y-value decreases.

Example: y = -2x + 3 has a negative gradient.
Key Concept Flip

A line segment has a length of 10 units and one endpoint at (1, 1). If the x-coordinate of the other endpoint is 7, what are the possible y-coordinates?

Answer Flip

Using the distance formula: 10 = √[(7-1)² + (y-1)²]. Solving for y: 100 = 36 + (y-1)², so (y-1)² = 64. Thus y-1 = ±8, giving y = 9 or y = -7.

Key Concept Flip

What does a gradient of zero indicate about a line?

Answer Flip

A gradient of zero indicates that the line is horizontal. The y-value remains constant, regardless of the x-value.

Example: the line y = 5 has a gradient of zero.
Key Concept Flip

If the gradient of a line is undefined, describe the orientation of the line.

Answer Flip

An undefined gradient means the line is vertical. This occurs when the change in x is zero (division by zero). The x-value remains constant, regardless of the y-value.

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3.1 Coordinates 3.3 Equations of lines

More topics in Unit 3 — Coordinate geometry

Gradient and length sits alongside these Mathematics decks in the same syllabus unit. Each uses the same spaced-repetition system, so progress in one informs the next.

Cambridge syllabus keywords to use in your answers

These are the official Cambridge 0580 terms tagged to this section. Mark schemes credit responses that use the exact term — weave them into your answers verbatim rather than paraphrasing.

gradient slope rise over run length distance distance formula Pythagoras midpoint midpoint formula

Related Mathematics guides

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How to study this Gradient and length deck

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