Gradient and length
Cambridge IGCSE Mathematics (0580) · Unit 3: Coordinate geometry · 9 flashcards
Gradient and length is topic 3.2 in the Cambridge IGCSE Mathematics (0580) syllabus , positioned in Unit 3 — Coordinate geometry , alongside Coordinates and Equations of lines.
This topic is examined across Paper 1 (Core) or Paper 2 (Extended) — non-calculator — and Paper 3 (Core) or Paper 4 (Extended) — calculator.
The deck below contains 9 flashcards — 5 key concepts — covering the precise wording mark schemes reward.
Questions this Gradient and length deck will help you answer
- › Explain the meaning of 'rise over run' in the context of gradient.
- › Describe how the Pythagorean theorem relates to finding the distance between two points on a coordinate plane.
- › Explain what a negative gradient indicates about the slope of a line.
- › What does a gradient of zero indicate about a line?
- › If the gradient of a line is undefined, describe the orientation of the line.
What is the formula to calculate the gradient (m) of a line given two points (x₁, y₁) and (x₂, y₂)?
The gradient, often denoted as 'm', is calculated as the change in y divided by the change in x. The formula is: m = (y₂ - y₁) / (x₂ - x₁).
Explain the meaning of 'rise over run' in the context of gradient.
'Rise over run' is a visual representation of gradient. 'Rise' refers to the vertical change (change in y), and 'run' refers to the horizontal change (change in x). The gradient is the ratio of the rise to the run.
Calculate the length of the line segment connecting points A(2, 3) and B(5, 7).
Use the distance formula (Pythagoras): √[(x₂ - x₁)² + (y₂ - y₁)²]. So, length AB = √[(5-2)² + (7-3)²] = √(9 + 16) = √25 = 5.
Describe how the Pythagorean theorem relates to finding the distance between two points on a coordinate plane.
The distance between two points is the hypotenuse of a right-angled triangle. The legs of the triangle are the difference in x-coordinates and the difference in y-coordinates. Thus, a² + b² = c² (distance squared).
Find the midpoint of the line segment joining the points (1, 4) and (5, 2).
The midpoint is found by averaging the x-coordinates and averaging the y-coordinates. Midpoint = [(x₁ + x₂) / 2, (y₁ + y₂) / 2]. Therefore, the midpoint is [(1+5)/2, (4+2)/2] = (3, 3).
Explain what a negative gradient indicates about the slope of a line.
A negative gradient indicates that the line slopes downwards from left to right. As the x-value increases, the y-value decreases.
A line segment has a length of 10 units and one endpoint at (1, 1). If the x-coordinate of the other endpoint is 7, what are the possible y-coordinates?
Using the distance formula: 10 = √[(7-1)² + (y-1)²]. Solving for y: 100 = 36 + (y-1)², so (y-1)² = 64. Thus y-1 = ±8, giving y = 9 or y = -7.
What does a gradient of zero indicate about a line?
A gradient of zero indicates that the line is horizontal. The y-value remains constant, regardless of the x-value.
If the gradient of a line is undefined, describe the orientation of the line.
An undefined gradient means the line is vertical. This occurs when the change in x is zero (division by zero). The x-value remains constant, regardless of the y-value.
More topics in Unit 3 — Coordinate geometry
Gradient and length sits alongside these Mathematics decks in the same syllabus unit. Each uses the same spaced-repetition system, so progress in one informs the next.
Cambridge syllabus keywords to use in your answers
These are the official Cambridge 0580 terms tagged to this section. Mark schemes credit responses that use the exact term — weave them into your answers verbatim rather than paraphrasing.
Related Mathematics guides
Long-read articles that go beyond the deck — cover the whole subject's common mistakes, high-yield content and revision pacing.
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