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Electromagnetic induction

5 learning objectives 3 core 2 extended

1. Overview

Electromagnetic induction is the process of generating electricity by using magnetic fields. It is the fundamental principle behind how power stations, wind turbines, and bicycle dynamos work, allowing us to convert mechanical energy into electrical energy.

Key Definitions

  • Electromagnetic Induction: The production of an electromotive force (e.m.f.) across an electrical conductor in a changing magnetic field.
  • Electromotive Force (e.m.f.): The electrical work done by a source in moving a unit charge around a complete circuit (measured in Volts).
  • Conductor: A material (usually a metal wire) that allows electrons to flow through it.
  • Magnetic Flux: A measure of the total magnetic field which passes through a given area.
  • Solenoid: A coil of wire that acts as an electromagnet when current flows through it.

Core Content

How Induction Occurs

An e.m.f. is induced in a conductor whenever it "cuts" through magnetic field lines. This can happen in two ways:

  1. Moving a conductor through a stationary magnetic field.
  2. Moving a magnet through or near a stationary conductor.
  3. Changing the strength of a magnetic field near a conductor.

Note: If the conductor is part of a complete circuit, the induced e.m.f. will cause an induced current to flow.

Experiment to Demonstrate Induction

To demonstrate induction in a lab, you need a sensitive center-zero ammeter (galvanometer), a coil of wire (solenoid), and a bar magnet.

  1. Connect the coil to the galvanometer.
  2. Push the North pole of the magnet into the coil. The needle will deflect in one direction.
  3. Hold the magnet still inside the coil. The needle will return to zero (no e.m.f. induced because no field lines are being cut).
  4. Pull the magnet out of the coil. The needle will deflect in the opposite direction.
📊A bar magnet being pushed into a coil of wire. The coil is connected to a galvanometer. Arrows show the motion of the magnet and the resulting deflection of the meter needle.

Factors Affecting the Magnitude of Induced e.m.f.

To increase the voltage/current produced, you can:

  • Increase the speed of the relative motion (move the magnet or wire faster).
  • Increase the strength of the magnetic field (use a more powerful magnet).
  • Increase the number of turns on the coil (more wire loops to cut the field lines).

Extended Content (Extended Curriculum Only)

Lenz’s Law: The Direction of Induced e.m.f.

The direction of an induced e.m.f. is such that it opposes the change causing it. This is a consequence of the Law of Conservation of Energy.

  • If you push a North pole into a coil, the coil will induce a North pole at that end to repel the incoming magnet.
  • If you pull a North pole out of a coil, the coil will induce a South pole at that end to attract the retreating magnet.

Fleming’s Right-Hand Rule (The Generator Rule)

While the Left-Hand Rule is for motors, the Right-Hand Rule is used to find the direction of induced current in a generator:

  • Thumb: Direction of Motion (Force).
  • First Finger: Direction of Magnetic Field (North to South).
  • Second Finger: Direction of Induced Current.
📊A right hand with the thumb, first finger, and second finger held at right angles to each other, labeled with Motion, Field, and Current respectively.

Key Equations

In IGCSE, calculations are rare for this specific sub-topic, but you must understand the relationships:

Variable Symbol Unit
Electromotive Force $e.m.f.$ or $V$ Volts (V)
Magnetic Field Strength $B$ Tesla (T)
Current $I$ Amperes (A)

Proportionality: $e.m.f. \propto \text{Number of turns} \times \frac{\text{Change in Magnetic Flux}}{\text{Time}}$


Common Mistakes to Avoid

  • Wrong: Thinking a stationary magnet inside a coil induces a voltage. ✓ Right: An e.m.f. is ONLY induced when there is relative motion (field lines are being cut).
  • Wrong: Assuming the induced e.m.f. stays at a maximum if the magnet is strong. ✓ Right: The e.m.f. exists only while the flux is changing; if the magnet stops moving, the e.m.f. drops to zero immediately.
  • Wrong: Thinking only the magnet can move. ✓ Right: Moving the coil while keeping the magnet still produces the exact same effect.
  • Wrong: Using your left hand for generator/induction questions. ✓ Right: Always use the Right-Hand Rule for induction and the Left-Hand Rule for the motor effect.
  • Wrong: Forgetting that gravity accelerates objects. ✓ Right: If a magnet falls through a coil, the e.m.f. at the bottom (exit) is usually larger than at the top (entry) because the magnet is moving faster.

Exam Tips

  1. Keywords: Always use the phrase "cutting magnetic field lines" when explaining how an e.m.f. is induced. It is the most common phrase on mark schemes.
  2. Direction Matters: If a question asks what happens when you reverse the magnet, the answer is always that the direction of the induced e.m.f./current reverses.
  3. Circuit vs. Voltage: Remember that an e.m.f. is induced even if the circuit is broken, but an induced current only flows if there is a complete circuit.

Exam-Style Questions

Practice these original exam-style questions to test your understanding. Each question mirrors the style, structure, and mark allocation of real Cambridge 0625 Theory papers.

Exam-Style Question 1 — Short Answer [6 marks]

Question:

A student investigates electromagnetic induction using the apparatus shown. A coil of wire is connected to a sensitive galvanometer. A strong bar magnet is held with its north pole facing the coil.

📊A coil of wire connected to a galvanometer. A bar magnet is positioned near the coil, with the North pole facing the coil. The magnet is held stationary.

(a) Describe what the student observes on the galvanometer when the magnet is suddenly moved quickly towards the coil. [3]

(b) State three ways the student could change the experiment to increase the size of the galvanometer deflection. [3]

Worked Solution:

(a)

  1. The galvanometer needle deflects. The movement of the magnet causes a change in the magnetic field linking the coil.
  2. The needle deflects in one direction, then returns to zero. The galvanometer measures the induced current, which is only present when the magnetic field is changing.
  3. The deflection is temporary. Once the magnet stops moving, the magnetic field linking the coil stops changing and the induced current stops.

How to earn full marks:

  • Correctly state that the galvanometer deflects (shows a reading).
  • Correctly state that the deflection is temporary (needle returns to zero).
  • Correctly state that the deflection occurs only while the magnet is moving.

(b)

  1. Use a stronger magnet. A stronger magnet will produce a larger change in magnetic flux linkage.
  2. Move the magnet faster. Moving the magnet faster will cause a greater rate of change of magnetic flux linkage.
  3. Use a coil with more turns. More turns will increase the induced e.m.f. for the same change in magnetic flux linkage.

How to earn full marks:

  • For each correct suggestion, award 1 mark.
  • Do NOT accept suggestions that involve changing the galvanometer.
  • Do NOT accept "use a bigger magnet" - must state "stronger".
  • Do NOT accept "use a bigger coil" - must state "more turns".

Common Pitfall: Remember that electromagnetic induction requires a changing magnetic field. A stationary magnet, no matter how strong, will not induce a current in the coil. Also, be specific when suggesting improvements; "bigger" is vague, while "stronger magnet" or "more turns" are clear and precise.

Exam-Style Question 2 — Extended Response [8 marks]

Question:

A bicycle dynamo is used to power the bicycle's headlights. The dynamo contains a rotating magnet near a coil of wire.

(a) Explain how the rotation of the magnet generates an electromotive force (e.m.f.) in the coil. [4]

(b) The dynamo generates an e.m.f. of 6.0 V when the bicycle is traveling at 5.0 m/s. The bicycle then slows down to 2.5 m/s. Assume the e.m.f. is directly proportional to the speed of the bicycle. Calculate the new e.m.f. generated by the dynamo. [2]

(c) The headlights have a resistance of 12 $\Omega$. Calculate the current flowing through the headlights when the bicycle is traveling at 2.5 m/s. [2]

Worked Solution:

(a)

  1. The rotating magnet causes a changing magnetic field in the coil. The magnet's rotation causes the magnetic field lines to cut through the coil.
  2. This changing magnetic field induces an e.m.f. in the coil. Electromagnetic induction occurs when a conductor experiences a changing magnetic field.
  3. The e.m.f. is generated because the magnetic flux linkage is changing. The number of magnetic field lines passing through the coil is constantly increasing and decreasing.
  4. This changing flux linkage induces a voltage according to Faraday's Law. Faraday's Law states that the induced e.m.f. is proportional to the rate of change of magnetic flux linkage.

How to earn full marks:

  • Correctly state that the rotating magnet causes a changing magnetic field.
  • Correctly state that this changing magnetic field induces an e.m.f.
  • Mention magnetic flux linkage is changing.
  • Mention Faraday's Law (either by name, or in effect).

(b)

  1. Determine the ratio of the speeds: 2.5 m/s / 5.0 m/s = 0.5 The new speed is half the original speed.
  2. Calculate the new e.m.f.: 6.0 V $\times$ 0.5 = 3.0 V Since the e.m.f. is directly proportional to the speed, halve the original e.m.f. $\boxed{e.m.f. = 3.0 \ V}$

How to earn full marks:

  • Shows the division calculation leading to 0.5
  • Correct final answer of 3.0 V.

(c)

  1. Use Ohm's Law: $V = IR$ and rearrange to $I = V/R$ Ohm's Law relates voltage, current, and resistance.
  2. Substitute the values: $I = 3.0 \ V / 12 \ \Omega = 0.25 \ A$ Use the calculated voltage from (b) and the given resistance. $\boxed{I = 0.25 \ A}$

How to earn full marks:

  • Correctly states Ohm's Law (or the rearranged form)
  • Correct final answer of 0.25 A. Error Carried Forward (ECF) from (b) is allowed.

Common Pitfall: In part (a), many students forget to mention the changing magnetic field as the key to electromagnetic induction. Also, remember to use the correct units in your calculations and to show your working clearly, especially when using Ohm's Law.

Exam-Style Question 3 — Short Answer [5 marks]

Question:

A transformer is used to step down the voltage from a 230 V mains supply to 12 V to operate a small electronic device.

(a) State the purpose of a transformer. [1]

(b) Describe the construction of a basic transformer. [2]

(c) Suggest one reason why the output voltage of the transformer might be slightly less than 12 V in practice. [2]

Worked Solution:

(a)

  1. A transformer is used to increase or decrease voltage. Transformers are used to step-up or step-down voltage.

How to earn full marks:

  • Correctly states that a transformer changes voltage.

(b)

  1. A transformer consists of two coils of wire. The coils are electrically isolated from each other.
  2. The coils are wound around a shared iron core. The iron core helps to concentrate the magnetic field.

How to earn full marks:

  • Correctly states that there are two coils of wire.
  • Correctly states that the coils are wound around an iron core.

(c)

  1. Energy losses due to resistance in the wires. The wires in the coils have some resistance, which causes energy to be lost as heat.
  2. Energy losses due to eddy currents in the core. Eddy currents are induced in the core, which cause energy to be lost as heat.

How to earn full marks:

  • Correctly suggests energy loss due to resistance in the wires OR eddy currents in the core.
  • Do NOT accept "not 100% efficient" without a specific reason.
  • Do NOT accept "transformer is old".

Common Pitfall: Students often state that transformers are "not 100% efficient" without explaining why. To get full marks, you need to identify specific reasons for energy loss, such as resistance in the coils or eddy currents in the core.

Exam-Style Question 4 — Extended Response [10 marks]

Question:

A wireless phone charger uses electromagnetic induction to transfer energy from a charging base to a phone. The charging base contains a coil connected to an alternating current (AC) power supply. The phone contains another coil. When the phone is placed on the charging base, the coils are close together.

(a) Explain how energy is transferred from the charging base to the phone. [4]

(b) The charging base operates at a frequency of 150 kHz. Calculate the period of one cycle of the alternating current. [2]

(c) The primary coil in the charging base has 200 turns and is connected to a 5.0 V AC supply. The secondary coil in the phone needs to provide 4.0 V. Calculate the number of turns required in the secondary coil, assuming the transformer is ideal (100% efficient). [2]

(d) In reality, the wireless charger is not 100% efficient. Suggest two reasons why the efficiency is less than 100%. [2]

Worked Solution:

(a)

  1. An alternating current in the charging base coil creates a changing magnetic field. The AC current constantly changes direction, producing a fluctuating magnetic field.
  2. This changing magnetic field links with the coil in the phone. The magnetic field lines from the base coil pass through the phone's coil.
  3. This induces an alternating e.m.f. in the phone's coil. Electromagnetic induction occurs because of the changing magnetic field.
  4. This induced e.m.f. drives an alternating current in the phone's coil, charging the battery. The induced current provides the energy to charge the phone's battery.

How to earn full marks:

  • Correctly states that AC creates a changing magnetic field.
  • Correctly states that the changing magnetic field links with the phone's coil.
  • Correctly states that this induces an e.m.f.
  • Correctly states that this e.m.f. drives a current.

(b)

  1. Use the formula: $T = 1/f$ The period is the inverse of the frequency.
  2. Substitute the value: $T = 1 / 150000 \ Hz = 6.67 \times 10^{-6} \ s$ Ensure the frequency is in Hz. $\boxed{T = 6.67 \times 10^{-6} \ s}$ (or 6.67 $\mu$s)

How to earn full marks:

  • Correctly states the formula $T = 1/f$.
  • Correct final answer of $6.67 \times 10^{-6} \ s$ (or equivalent).

(c)

  1. Use the transformer equation: $V_p / V_s = N_p / N_s$ The transformer equation relates the voltage and number of turns in the primary and secondary coils.
  2. Rearrange to find $N_s$: $N_s = (V_s / V_p) \times N_p$ Rearrange the equation to solve for the number of turns in the secondary coil.
  3. Substitute the values: $N_s = (4.0 \ V / 5.0 \ V) \times 200 = 160$ Plug in the given values. $\boxed{N_s = 160}$

How to earn full marks:

  • Correctly states the transformer equation.
  • Correctly rearranges the equation to find $N_s$.
  • Correct final answer of 160 (no units required).

(d)

  1. Some magnetic field lines may not link with the secondary coil. Not all of the magnetic flux produced by the primary coil will pass through the secondary coil.
  2. Energy losses due to resistance in the wires. The wires in the coils have some resistance, which causes energy to be lost as heat.

How to earn full marks:

  • For each correct reason, award 1 mark.
  • Award a maximum of 2 marks.
  • Do NOT accept "not 100% efficient" without a specific reason.

Common Pitfall: In part (a), remember that the alternating current is crucial for creating the changing magnetic field needed for induction. In part (d), avoid vague answers like "energy loss" and instead specify the mechanisms causing the loss, such as magnetic flux leakage or resistance in the coils.

Practise Electromagnetic induction with recent IGCSE Physics past papers

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Frequently Asked Questions: Electromagnetic induction

What is Electromagnetic Induction in Electromagnetic induction?

Electromagnetic Induction: The production of an electromotive force (e.m.f.) across an electrical conductor in a changing magnetic field.

What is Electromotive Force (e.m.f.) in Electromagnetic induction?

Electromotive Force (e.m.f.): The electrical work done by a source in moving a unit charge around a complete circuit (measured in Volts).

What is Conductor in Electromagnetic induction?

Conductor: A material (usually a metal wire) that allows electrons to flow through it.

What is Magnetic Flux in Electromagnetic induction?

Magnetic Flux: A measure of the total magnetic field which passes through a given area.

What is Solenoid in Electromagnetic induction?

Solenoid: A coil of wire that acts as an electromagnet when current flows through it.