Momentum
Cambridge IGCSE Physics (0625) · Unit 1: Motion, forces and energy · 8 flashcards
Momentum is topic 1.6 in the Cambridge IGCSE Physics (0625) syllabus , positioned in Unit 1 — Motion, forces and energy , alongside Physical quantities and measurement techniques, Motion and Mass and weight. In one line: Resultant force is defined as the rate of change of momentum. It is the change in momentum per unit time.
This topic is examined in Paper 1 (multiple-choice) and Papers 3/4 (theory), plus Paper 5 or Paper 6 (practical / alternative to practical). It is a Supplement (Extended-tier) topic, so it appears only on the Extended-tier papers.
The deck below contains 8 flashcards — 1 definition — covering the precise wording mark schemes reward. Use the definition card to lock down command-word answers (define, state), then move on to the concept and application cards to handle explain, describe and compare questions.
Resultant force in terms of momentum
Resultant force is defined as the rate of change of momentum. It is the change in momentum per unit time.
What the Cambridge 0625 syllabus says
Official 2026-2028 specThese are the exact learning objectives Cambridge sets for this topic. Match the command word (Describe, Explain, State, etc.) in your answer to score full marks.
- Define Define momentum as mass x velocity; recall and use the equation p = mv Supplement
- Define Define impulse as force x time for which force acts; recall and use the equation impulse = FAt = A(mv) Supplement
- Apply Apply the principle of the conservation of momentum to solve simple problems in one dimension Supplement
- Define Define resultant force as the change in momentum per unit time; recall and use the equation F= Supplement
Define momentum. A 0.25 kg ball is traveling at 12 m/s. Calculate its momentum.
Momentum is defined as the product of an object's mass and its velocity.
p = mv
p = 0.25 kg * 12 m/s
p = 3 kg m/s
The momentum of the ball is 3 kg m/s.
A toy car of mass 0.1 kg has a momentum of 0.5 kg m/s. State the velocity of the toy car.
p = mv
v = p/m
v = 0.5 kg m/s / 0.1 kg
v = 5 m/s
The toy car's velocity is 5 m/s.
A footballer kicks a stationary ball of mass 0.45 kg. The force of the kick is 80 N and the foot is in contact with the ball for 0.12 s. Calculate the change in momentum of the ball.
Impulse = Force x Time = Change in momentum
Impulse = 80 N x 0.12 s = 9.6 Ns
Change in momentum = 9.6 kg m/s
Impulse is the change in momentum, so we calculate force multiplied by time to find the change in momentum.
A cricket ball of mass 0.16 kg is travelling at 35 m/s. A fielder catches the ball, bringing it to rest in 0.04 s. State the impulse experienced by the fielder.
Impulse = Change in momentum = m(v-u)
Impulse = 0.16 kg x (0 m/s - 35 m/s) = -5.6 Ns
Impulse experienced by the fielder is 5.6 Ns (or -5.6 Ns, depending on direction convention). The negative sign indicates the force acts in the opposite direction to the ball's initial motion. The fielder is experiencing the change in momentum of the ball.
A 2 kg trolley is moving at 3 m/s to the right. It collides with a stationary 1 kg trolley. After the collision, the 2 kg trolley is moving at 2 m/s to the right. Calculate the velocity of the 1 kg trolley after the collision. Assume the collision is along a straight line.
Formula: Total momentum before = Total momentum after
(m₁v₁) + (m₂v₂) = (m₁v₁') + (m₂v₂')
Working:
(2 kg * 3 m/s) + (1 kg * 0 m/s) = (2 kg * 2 m/s) + (1 kg * v₂')
6 kg m/s = 4 kg m/s + (1 kg * v₂')
2 kg m/s = 1 kg * v₂'
v₂' = 2 m/s
Answer: The velocity of the 1 kg trolley after the collision is 2 m/s to the right. (2 marks)
A ball is dropped onto the ground and bounces back up. Explain why the momentum of the ball is NOT conserved during this collision, even though momentum is conserved overall.
Momentum is conserved in a closed system with no external forces. When the ball hits the ground, the system is NOT closed because the Earth exerts an external force on the ball (and the ball exerts an equal and opposite force on the Earth). While the *total* momentum of the ball + Earth system *is* conserved, the momentum of the ball alone is not. The change in the ball's momentum is equal and opposite to the change in the Earth's momentum, but because the Earth's mass is so large, its change in velocity is negligible. Friction and air resistance also apply external forces.
Define resultant force in terms of momentum.
Resultant force is defined as the rate of change of momentum. It is the change in momentum per unit time.
A car of mass 1200 kg increases its velocity from 10 m/s to 25 m/s in 5 seconds. Calculate the resultant force acting on the car.
F = (mv - mu)/t
F = (1200 kg * 25 m/s - 1200 kg * 10 m/s) / 5 s
F = (30000 kg m/s - 12000 kg m/s) / 5 s
F = 18000 kg m/s / 5 s
F = 3600 N
The resultant force is the rate of change of momentum. We calculate the change in momentum and divide by the time taken.
Key Questions: Momentum
Define resultant force in terms of momentum.
Resultant force is defined as the rate of change of momentum. It is the change in momentum per unit time.
Tips to avoid common mistakes in Momentum
- ● Learn that a resultant force causes acceleration, that acceleration changes velocity, and that changing velocity is exactly what changes momentum.
- ● Be sure every numerical answer comes with its correct SI unit.
- ● Revisit the definitions of impulse and momentum, and work through lots of real-world examples.
- ● To tackle momentum problems, write down the equation, clearly indicate the positive and negative directions of velocity, and show the correct change of momentum sign.
- ● Remember the big rule for equilibrium problems about moments: the total moment is zero no matter what point you choose as your pivot.
More topics in Unit 1 — Motion, forces and energy
Momentum sits alongside these Physics decks in the same syllabus unit. Each uses the same spaced-repetition system, so progress in one informs the next.
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Cambridge syllabus keywords to use in your answers
These are the official Cambridge 0625 terms tagged to this section. Mark schemes credit responses that use the exact term — weave them into your answers verbatim rather than paraphrasing.
Key terms covered in this Momentum deck
Every term below is defined in the flashcards above. Use the list as a quick recall test before your exam — if you can't define one of these in your own words, flip back to that card.
Related Physics guides
Long-read articles that go beyond the deck — cover the whole subject's common mistakes, high-yield content and revision pacing.
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