4.5.4

Force on a current-carrying conductor

Cambridge IGCSE Physics (0625)  · Unit 4: Electricity and magnetism  · 6 flashcards

Force on a current-carrying conductor is topic 4.5.4 in the Cambridge IGCSE Physics (0625) syllabus , positioned in Unit 4 — Electricity and magnetism , alongside Simple phenomena of magnetism, Electric charge and Electric current.

This topic is examined in Paper 1 (multiple-choice) and Papers 3/4 (theory), plus Paper 5 or Paper 6 (practical / alternative to practical).

The deck below contains 6 flashcards — covering the precise wording mark schemes reward.

What the Cambridge 0625 syllabus says

Official 2026-2028 spec

These are the exact learning objectives Cambridge sets for this topic. Match the command word (Describe, Explain, State, etc.) in your answer to score full marks.

  1. Describe Describe an experiment to show that a force acts on a current-carrying conductor in a magnetic field, including the effect of reversing: (a) the current (b) the direction of the field
  2. Recall Recall and use the relative directions of force, magnetic field and current Supplement
  3. Determine Determine the direction of the force on beams of charged particles in a magnetic field Supplement
Key Concept Flip

Describe an experiment to demonstrate the force acting on a 7.2 cm length of wire carrying a current in a magnetic field. Your description should include how you would show the effect of reversing the current.

Answer Flip

1. Set up a strong horseshoe magnet with the poles facing horizontally.
2. Suspend a straight length of wire (approximately 7.2 cm) horizontally between the poles of the magnet, so it is perpendicular to the magnetic field. This can be done using thin, flexible wires connected to a power supply.
3. Connect the wire in a circuit with a power supply, ammeter and a switch.
4. Close the switch and observe the movement of the wire. The wire will be deflected upwards or downwards due to the force acting on it.
5. To demonstrate the effect of reversing the current, reverse the connections to the power supply. Observe that the wire now deflects in the opposite direction. The direction of the force on the wire changes when the current is reversed.

Key Concept Flip

State what happens to the force on a current-carrying conductor in a magnetic field when: (a) the direction of the current is reversed; and (b) the direction of the magnetic field is reversed.

Answer Flip

(a) When the direction of the current is reversed, the direction of the force on the conductor is also reversed. The force acts in the opposite direction.
(b) When the direction of the magnetic field is reversed, the direction of the force on the conductor is also reversed. The force acts in the opposite direction.

Key Concept Flip

A straight wire, 0.1 m long, carries a current of 8.0 A perpendicular to a uniform magnetic field of 0.25 T. Calculate the magnitude of the force on the wire.

Answer Flip

Force, F = BIl
F = 0.25 T * 8.0 A * 0.1 m
F = 0.2 N

The formula F=BIl is used to calculate the force on a current carrying conductor in a magnetic field. B is magnetic field strength, I is current, and l is length of conductor in the field.

Key Concept Flip

A wire carries a current from left to right through a magnetic field which points into the page. State the direction of the force on the wire.

Answer Flip

The force is upwards.

This can be determined using Fleming's Left Hand Rule. Point your index finger in the direction of the magnetic field (into the page), your middle finger in the direction of the current (left to right), and your thumb will point in the direction of the force (upwards).

Key Concept Flip

A beam of electrons, each carrying a charge of -1.6 x 10^-19 C, travels horizontally at a speed of 2.0 x 10^7 m/s. It enters a uniform magnetic field of 0.1 T directed vertically upwards. Determine the magnitude of the magnetic force acting on a single electron.

Answer Flip

Force on a single electron is given by F = Bqv, where B is the magnetic field strength, q is the charge, and v is the velocity.
F = (0.1 T) * (1.6 x 10^-19 C) * (2.0 x 10^7 m/s) = 3.2 x 10^-13 N. The force is 3.2 x 10^-13 N. This calculation uses the formula for the magnetic force on a moving charge.

Key Concept Flip

A beam of positively charged ions is moving horizontally into a uniform magnetic field directed into the page. State the direction of the magnetic force acting on the ion beam. Explain your reasoning.

Answer Flip

The direction of the force is upwards. Applying Fleming's Left Hand Rule (or the right-hand rule for positive charges), with the magnetic field (middle finger) pointing into the page and the current (forefinger) pointing to the right, the force (thumb) points upwards. Thus, the beam deflects upwards.

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4.5.3 Magnetic effect of a current 4.5.5 The d.c. motor

More topics in Unit 4 — Electricity and magnetism

Force on a current-carrying conductor sits alongside these Physics decks in the same syllabus unit. Each uses the same spaced-repetition system, so progress in one informs the next.

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