Circuit diagrams and circuit components
Cambridge IGCSE Physics (0625) · Unit 4: Electricity and magnetism · 4 flashcards
Circuit diagrams and circuit components is topic 4.3.1 in the Cambridge IGCSE Physics (0625) syllabus , positioned in Unit 4 — Electricity and magnetism , alongside Simple phenomena of magnetism, Electric charge and Electric current.
This topic is examined in Paper 1 (multiple-choice) and Papers 3/4 (theory), plus Paper 5 or Paper 6 (practical / alternative to practical).
The deck below contains 4 flashcards — covering the precise wording mark schemes reward.
What the Cambridge 0625 syllabus says
Official 2026-2028 specThese are the exact learning objectives Cambridge sets for this topic. Match the command word (Describe, Explain, State, etc.) in your answer to score full marks.
- Draw Draw and interpret circuit diagrams containing cells, batteries, power supplies, generators, potential dividers, switches, resistors (fixed and variable), heaters, thermistors (NTC only), light-dependent resistors (LDRs), lamps, motors, bells, ammeters, voltmeters, magnetising coils, transformers, fuses and relays and know how these components behave in the circuit
- Draw Draw and interpret circuit diagrams containing diodes and light-emitting diodes (LEDs) and know how these components behave in the circuit Supplement
A circuit contains a 12V battery, a switch, a 10Ω resistor, and an ammeter connected in series. The switch is closed. Calculate the reading on the ammeter.
Formula: V = IR
Rearrange to find current: I = V/R
I = 12V / 10Ω
I = 1.2A
The ammeter reading will be 1.2 Amperes. Ohm's Law relates voltage, current, and resistance in a circuit.
Describe how the resistance of an NTC thermistor changes as its temperature increases, and state how this change would affect the current in a series circuit containing the thermistor and a fixed resistor powered by a battery.
As the temperature of an NTC thermistor increases, its resistance decreases.
In a series circuit, if the thermistor's resistance decreases, the total resistance of the circuit decreases. Since the voltage of the battery remains constant, the current in the circuit will increase (due to Ohm's Law: I = V/R).
A circuit contains a 3.0 V battery connected in series with a diode and a 100 Ω resistor. When the diode is forward biased, its forward voltage drop is approximately 0.7 V. Calculate the current flowing through the circuit.
Current, I = (Voltage of battery - Voltage drop of diode) / Resistance
I = (3.0 V - 0.7 V) / 100 Ω
I = 2.3 V / 100 Ω
I = 0.023 A
Explanation: The current is calculated using Ohm's Law, but first accounting for the voltage drop across the forward-biased diode.
Explain why a diode is often included in a circuit with an LED.
A diode is often included in a circuit with an LED to protect the LED from reverse voltage and excessive current. Diodes allow current to flow in only one direction. If the voltage polarity is accidentally reversed, the diode will block the current, preventing damage to the LED. They also limit current, increasing LED lifespan.
More topics in Unit 4 — Electricity and magnetism
Circuit diagrams and circuit components sits alongside these Physics decks in the same syllabus unit. Each uses the same spaced-repetition system, so progress in one informs the next.
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