20.2 A2 Level

Force on a current-carrying conductor

Cambridge A-Level Physics (9702)  · Unit 20: Magnetic fields  · 7 flashcards

Force on a current-carrying conductor is topic 20.2 in the Cambridge A-Level Physics (9702) syllabus , positioned in Unit 20 — Magnetic fields , alongside Concept of a magnetic field, Force on a moving charge and Magnetic fields due to currents.  In one line: The force F on a current-carrying conductor is given by F = BILsinθ, where B is the magnetic flux density, I is the current, L is the length of the conductor in the field, and θ is the angle between the conductor and the magnetic field.

Marked as A2 Level: examined at A Level in Paper 4 (A Level Structured Questions) and Paper 5 (Planning, Analysis and Evaluation). It is not tested on the AS-only papers (Papers 1, 2 and 3).

The deck below contains 7 flashcards — 2 definitions, 3 key concepts and 2 calculations — covering the precise wording mark schemes reward.  Use the 2 definition cards to lock down command-word answers (define, state), then move on to the concept and calculation cards to handle explain, describe, calculate and compare questions.

Key definition

Formula that relates the force on a current-carrying conductor to the magnetic field, current, and length

The force F on a current-carrying conductor is given by F = BILsinθ, where B is the magnetic flux density, I is the current, L is the length of the conductor in the field, and θ is the angle between the conductor and the magnetic field.

What the Cambridge 9702 syllabus says

Official 2025-2027 spec · A2 Level

These are the exact learning outcomes Cambridge sets for this topic. The candidate is expected to be able to do each of these on the relevant paper.

  1. understand that a force might act on a current-carrying conductor placed in a magnetic field
  2. recall and use the equation F = BIL sin θ, with directions as interpreted by Fleming’s left-hand rule
  3. define magnetic flux density as the force acting per unit current per unit length on a wire placed at right- angles to the magnetic field

Cambridge syllabus keywords to use in your answers

These are the official Cambridge 9702 terms tagged to this section. Mark schemes credit responses that use the exact term — weave them into your answers verbatim rather than paraphrasing.

current-carrying conductor Fleming’s left-hand rule magnetic flux density

Tips to avoid common mistakes in Force on a current-carrying conductor

Key Concept Flip

Under what conditions does a force act on a current-carrying conductor placed in a magnetic field?

Answer Flip

A force acts on a current-carrying conductor in a magnetic field when the conductor is not parallel to the magnetic field lines. The force is maximized when the conductor is perpendicular to the field.

Definition Flip

State the formula that relates the force on a current-carrying conductor to the magnetic field, current, and length.

Answer Flip

The force F on a current-carrying conductor is given by F = BILsinθ, where B is the magnetic flux density, I is the current, L is the length of the conductor in the field, and θ is the angle between the conductor and the magnetic field.

Key Concept Flip

Explain Fleming's left-hand rule and how it is used.

Answer Flip

Fleming's left-hand rule gives the direction of the force on a current-carrying conductor in a magnetic field. With your Thumb, First finger, and Second finger at right angles, the First finger points in the direction of the Field, the Second finger points in the direction of the Current, and the Thumb points in the direction of the Force.

Definition Flip

Define magnetic flux density (B).

Answer Flip

Magnetic flux density (B) is defined as the force acting per unit current per unit length on a wire placed at right angles to the magnetic field. Its unit is the Tesla (T).

Calculation Flip

A 5 cm wire carrying a current of 3 A is placed perpendicular to a magnetic field of 0.6 T. Calculate the force on the wire.

Answer Flip

Using F = BILsinθ, where θ = 90°, F = (0.6 T)(3 A)(0.05 m)(sin 90°) = 0.09 N. Therefore, the force on the wire is 0.09 N.

Key Concept Flip

Describe how the magnitude of the force on a current-carrying wire changes as the angle between the wire and magnetic field varies from 0 to 90 degrees.

Answer Flip

The force is zero when the wire is parallel (0 degrees) to the magnetic field (sin 0° = 0). The force increases as the angle increases, reaching a maximum when the wire is perpendicular (90 degrees) to the field (sin 90° = 1).

Calculation Flip

A wire of length 0.2m, carrying a current of 2A, experiences a force of 0.08N when placed in a magnetic field. If the wire is perpendicular to the field, what is the magnetic flux density?

Answer Flip

Using F = BILsinθ, and rearranging for B: B = F / (ILsinθ). Since θ = 90°, sin θ = 1. Therefore B = 0.08N / (2A * 0.2m) = 0.2T. The magnetic flux density is 0.2 Tesla.

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Read full revision notes on Force on a current-carrying conductor — definitions, equations, common mistakes, and exam tips.

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20.1 Concept of a magnetic field 20.3 Force on a moving charge

More topics in Unit 20 — Magnetic fields

Force on a current-carrying conductor sits alongside these A-Level Physics decks in the same syllabus unit. Each uses the same spaced-repetition system, so progress in one informs the next.

Key terms covered in this Force on a current-carrying conductor deck

Every term below is defined in the flashcards above. Use the list as a quick recall test before your exam — if you can't define one of these in your own words, flip back to that card.

Formula that relates the force on a current-carrying conductor to the magnetic field, current, and length
Magnetic flux density (B)

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